τ=VQIttau equals the fraction with numerator cap V cap Q and denominator cap I t end-fraction (Where is the first moment of area and is the thickness at the point of interest). Practice Problem: Axial Loading A steel rod ( ) is 2 meters long and has a cross-sectional area of . If it is subjected to a tensile load of , calculate the total elongation. Solution: Identify Givens: Apply Formula: Calculate:
σ=PAsigma equals the fraction with numerator cap P and denominator cap A end-fraction The deformation per unit length. Mechanics of Materials - Formulas and Problems:...
The most basic concepts involve forces applied along the longitudinal axis of a member. The internal force per unit area. τ=VQIttau equals the fraction with numerator cap V
δ=160,00080,000,000=0.002 m or 2 mmdelta equals the fraction with numerator 160 comma 000 and denominator 80 comma 000 comma 000 end-fraction equals 0.002 m or 2 mm Practice Problem: Bending Stress A rectangular beam ( ) experiences a maximum bending moment of . Determine the maximum bending stress. Solution: Find : Find : Apply Formula: Result: δ=160,00080,000,000=0
ϕ=TLGJphi equals the fraction with numerator cap T cap L and denominator cap G cap J end-fraction (Note: is the polar moment of inertia; for solid shafts). 3. Pure Bending
σmax=McIsigma sub m a x end-sub equals the fraction with numerator cap M c and denominator cap I end-fraction 4. Transverse Shear Internal shear forces ( ) result in shear stresses across the cross-section.